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Multiple identities on forum.

Feel free to talk about anything that you want.

Postby CBBB » Thu Jul 17, 2008 8:11 pm

Who is the constipated mathematician trying to work it out with a pencil?
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Postby denizaksulu » Thu Jul 17, 2008 8:28 pm

Bill wrote:
kangaroo wrote:do members from the forum get together?


Not really Kangaroo ~ it's not really that kind of forum that promotes off the keyboard meetings and people revealing their identity :shock: .

Mind you some do and according to some posts friendships have been made ~ on both sides of the divide .

It would be nice though but apart from the odd few forum members I can't see it happening.

Bill



Me, ODD? Now I am bothered. :?
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Postby denizaksulu » Thu Jul 17, 2008 8:31 pm

SSBubbles wrote:
tessintrnc wrote:
Bill wrote:
kangaroo wrote:do members from the forum get together?


Not really Kangaroo ~ it's not really that kind of forum that promotes off the keyboard meetings and people revealing their identity :shock: .

Mind you some do and according to some posts friendships have been made ~ on both sides of the divide .

It would be nice though but apart from the odd few forum members I can't see it happening.

Bill


I'll be odd in a couple of mths, 'cos I am hoping to meet some members!!! :lol:



Me too Tess! So if we are both odd, we must now be even! :lol:



With me, thats ODD again. :lol: :lol:
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Postby Magnus » Fri Jul 18, 2008 2:19 pm

bill cobbett wrote:Have been working hard on an infallible formula which finds the doppelganger of any member. So it is with great pleasure that I am unveiling it for your consideration and entertainment tonight.

Let us take the example of the member Magnus who some have accused, wrongly I'm sure, of having more than one persona.

Magnus = 2x(a+b)/??x-a = bcnumismaticology

No that can't be right. Let me make some minor adjustments to the coefficients and try again.

Magnus = 2x(a+b)/??x-a = bill cobbett

Doh! :?


I tried your formula too but all it gave me was the secret ingredient in Kentucky Fried Chicken. :lol:
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