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[Get Real!]

a.(a+3)=88^2 this the right one

That's like saying 88 = 88^2!!! How can that be?

[LENA]

Cyfo can I ask what is ^ ? Is it / like 12/3=4
??

Come on Lena you're a Uni student for christ's sake... squared!

Thanks Cyfo and Get real....

Come on I learn maths with the normal way not the keyboard way...sorry I dont know everything!

[Get Real!]

the answer is a=8 but how to solve this

Is that what is says on the question sheet?

[cyfo]

it is rectangle 11x8=88^2

but the problem is a.(a+3)=88^2 what the valiou for (a) .i know is 8 but how to solve it

[Sotos]

My girlfriend reminded me that it is a formula so here it is: http://www.math.vanderbilt.edu/~schectex/courses/cubic/

[Get Real!]

My girlfriend reminded me that it is a formula so here it is: http://www.math.vanderbilt.edu/~schectex/courses/cubic/

That looks like a Quadratic equation which requires values for "a", "b", and "c" to calculate. Anyway...

“a” cannot be equal to 8 look…. Just replace “a” with 8 from your original equation…

a.a.(a+3)=88

8*8*(8+3)=88

64*11=88 !!!

[cyfo]

Sotos you are not much helpfull here

[Get Real!]

I insist…

a*a*(a+3)=88

a^2(a+3)=88

a^2=88/(a+3)

a:=SquareRoot(88/(a+3))

[cyfo]

That looks like a Quadratic equation which requires values for "a", "b", and "c" to calculate. Anyway...

“a” cannot be equal to 8 look…. Just replace “a” with 8 from your original equation…

a.a.(a+3)=88

8*8*(8+3)=88

64*11=88 !!!

a.(a+3)=88^2
8.(8+3)=88^2

[Get Real!]

That looks like a Quadratic equation which requires values for "a", "b", and "c" to calculate. Anyway...

“a” cannot be equal to 8 look…. Just replace “a” with 8 from your original equation…

a.a.(a+3)=88

8*8*(8+3)=88

64*11=88 !!!

a.(a+3)=88^2
8.(8+3)=88^2

You've broken a rule here...

+ = -
* = /
^ = SquareRoot

so how can you throw the first "a" across and convert it to ^ ???? it has to be / !!!